1 solutions
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1
#include<bits/stdc++.h> using namespace std; int _(int x) { int l=0,r=1000000000,mid=0,s=0; while (l<=r) { mid=(l+r)/2; //cout<<mid<<endl; if(mid==x)break; else if(mid>x)r=mid; else l=mid; s++; } return s+1; } int main() { int a,b,c; cin>>a>>b>>c; cout<<_(a )+_(b)+_(c); }
- 1
Information
- ID
- 1840
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 10
- Tags
- # Submissions
- 8
- Accepted
- 5
- Uploaded By