1 solutions
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1
#include<bits/stdc++.h> using namespace std; int main() { char a[2001],b[2001]; cin>>a>>b; int c[2001],d[2001]; int len=strlen(a); for(int i=0;i<len;i++){c[i]=a[i]-48;d[i]=b[i]-48;} for(int i=0;i<len;i++)cout<<c[i]; cout<<"\n"; for(int i=0;i<len;i++)cout<<d[i]; }
- 1
Information
- ID
- 1774
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 7
- Tags
- # Submissions
- 64
- Accepted
- 15
- Uploaded By