#include <iostream>
using namespace std;
int main() {
    int n;
    cin >> n; 
    int total = n * (n + 1) * (2 * n + 1) / 6;
    cout << total << endl;  
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int a;
    int s=0;
    cin>>a;
    while(a!=1)
    {
        s+=a*a;
        a--;
    }
    s+=a*a;
    cout<<s;
}

C++ :

#include <iostream>
using namespace std;

int main() {
    int n;
    cin >> n;  // 读取金字塔的层数
    
    // 计算1² + 2² + ... + n²的和，使用公式n(n+1)(2n+1)/6
    int total = n * (n + 1) * (2 * n + 1) / 6;
    
    cout << total << endl;  // 输出总石块数
    return 0;
}