1 solutions

  • 0
    @ 2025-11-27 11:58:15

    C++ :

    
    #include<iostream>
    using namespace std;
    int n,a[1010],x,d; //x表示要存入的存钱罐的编号
    int main()
    {
        cin>>n>>d;
        for(int i=1;i<=d;i++)
        {
            cin>>x;
            a[x]+=i;//在编号为x的存钱罐存i元
        }
        for(int i=0;i<n;i++)
        {
            cout<<a[i]<<" ";//输出0到n-1每个存钱罐的钱数
        }
        return 0;
    }
    
    
    
    
    • 1

    Information

    ID
    62
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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