1 solutions
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0
C++ :
#include <algorithm> #include <cstdio> using namespace std; int n, ans; int main() { scanf("%d", &n); for (int i = 1; i <= n; i++) { int v = i % 10, t = i / 10, chk = 1; while (t) { if (t % 10 != v) chk = 0; t /= 10; } ans += chk; } printf("%d\n", ans); return 0; }
- 1
Information
- ID
- 47
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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