1 solutions

  • 0
    @ 2025-11-27 11:55:05

    C++ :

    #include <algorithm>
    #include <cstdio>
    using namespace std;
    int main() {
    	int n, i, j, k;
    	scanf("%d", &n);
    	k = n / 2;
    	for (i = 1; i <= n; i++) {
    	for (j = 1; j <= n; j++) {
    	if (abs(k - i + 1) + abs(k - j + 1) == k)
    	printf("#");
    	else
    	printf(".");
    	}
    	printf("\n");
    	}
    	return 0;
    }
    
    • 1

    Information

    ID
    46
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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