1 solutions
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0
C++ :
#include <algorithm> #include <cstdio> using namespace std; int main() { int n, i, j, k; scanf("%d", &n); k = n / 2; for (i = 1; i <= n; i++) { for (j = 1; j <= n; j++) { if (abs(k - i + 1) + abs(k - j + 1) == k) printf("#"); else printf("."); } printf("\n"); } return 0; }
- 1
Information
- ID
- 46
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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