1 solutions
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0
C++ :
#include <bits/stdc++.h> using namespace std; const int mod=1e9+7; int t,n,m,k; int C[1003][1003],mi[2003]; int main(){ for(int i=0;i<=1000;i++) for(int j=0;j<=i;j++) C[i][j]=(j==0 || j==i?1:C[i-1][j]+C[i-1][j-1]),C[i][j]%=mod; mi[0]=1; for(int i=1;i<=2000;i++) mi[i]=mi[i-1]*2%mod; scanf("%d",&t); while(t--){ scanf("%d%d%d",&n,&m,&k); if(m-2*k<0 || m-2*k>n-k) printf("0\n"); else printf("%lld\n",(1LL*C[n][k]*mi[m-2*k]%mod)*C[n-k][m-2*k]%mod); } return 0; }
- 1
Information
- ID
- 146
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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