1 solutions

  • 0
    @ 2025-11-27 11:59:57

    C++ :

    #include <iostream>
    #include <vector>
    using namespace std;
    
    const int N = 1e3 + 5;
    
    int n, k, maxn, col[N];
    vector<int> g[N];
    
    void dfs(int u, int fa, int cnt1, int cnt2) {
    	if(cnt2 > k) return;//比k大了 
    	maxn = max(maxn, cnt1);
    	for(int i = 0; i < g[u].size(); i++) {
    		int v = g[u][i];
    		if(v != fa) {
    			if(col[v] == 1) dfs(v, u, cnt1 + 1, cnt2 + 1);
    			else dfs(v, u, cnt1 + 1, cnt2);
    		}
    	} 
    }
    
    int main() {
    	cin >> n >> k;
    	for(int i = 1; i <= n; i++) cin >> col[i];
    	for(int i = 1; i < n; i++) {
    		int u, v;
    		cin >> u >> v;
    		g[u].push_back(v);
    		g[v].push_back(u);
    	}
    	for(int i = 1; i <= n; i++) {//暴力遍历 
    		if(col[i] == 1) dfs(i, 0, 1, 1);
    		else dfs(i, 0, 1, 0);
    	}
    	cout << maxn << endl;
    	return 0;
    }
    
    
    • 1

    Information

    ID
    145
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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