1 solutions
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0
C++ :
#include <iostream> #include <vector> using namespace std; const int N = 1e3 + 5; int n, k, maxn, col[N]; vector<int> g[N]; void dfs(int u, int fa, int cnt1, int cnt2) { if(cnt2 > k) return;//比k大了 maxn = max(maxn, cnt1); for(int i = 0; i < g[u].size(); i++) { int v = g[u][i]; if(v != fa) { if(col[v] == 1) dfs(v, u, cnt1 + 1, cnt2 + 1); else dfs(v, u, cnt1 + 1, cnt2); } } } int main() { cin >> n >> k; for(int i = 1; i <= n; i++) cin >> col[i]; for(int i = 1; i < n; i++) { int u, v; cin >> u >> v; g[u].push_back(v); g[v].push_back(u); } for(int i = 1; i <= n; i++) {//暴力遍历 if(col[i] == 1) dfs(i, 0, 1, 1); else dfs(i, 0, 1, 0); } cout << maxn << endl; return 0; }
- 1
Information
- ID
- 145
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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