1 solutions

  • 0
    @ 2025-11-27 11:59:02

    C++ :

    #include <algorithm>
    #include <cstdio>
    #include <vector>
    
    using namespace std;
    
    const int N = 1e5 + 5;
    
    int n;
    vector<vector<pair<int, int>>> e;
    
    long long s, mx;
    
    void dfs(int u, int f, long long d) {
        mx = max(mx, d);
        for (auto p : e[u]) {
            if (p.first != f) dfs(p.first, u, d + p.second);
        }
    }
    
    int main() {
        scanf("%d", &n);
        e.resize(n + 1);
        for (int i = 1; i < n; i++) {
            int u, v, w;
            scanf("%d%d%d", &u, &v, &w);
            e[u].emplace_back(make_pair(v, w));
            e[v].emplace_back(make_pair(u, w));
            s += w;
        }
        dfs(1, 0, 0);
        printf("%lld\n", s * 2 - mx);
        return 0;
    }
    
    • 1

    Information

    ID
    123
    Time
    1000ms
    Memory
    512MiB
    Difficulty
    (None)
    Tags
    # Submissions
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