1 solutions
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0
C++ :
#include <iostream> using namespace std; const int mod=1000000007; int n,a,b,c; int jiyi[200010]; //顾名思义,记忆化数组 int baosou(int dangqiann) //求n为dangqiann时有多少种操作序列 { if(dangqiann<=c) { return 1; } if(jiyi[dangqiann]) { return jiyi[dangqiann]; } return jiyi[dangqiann]=(baosou(dangqiann-a)+baosou(dangqiann-b))%mod; } int main() { cin>>n>>a>>b>>c; cout<<baosou(n); return 0; }
- 1
Information
- ID
- 116
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
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