1 solutions
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0
C++ :
#include <iostream> #include <algorithm> #include <cstdio> #include <cstring> using namespace std; const int N=2e5+15; int col[N]; int e[N],ne[N],h[N],idx,w[N]; int f[N],g[N],mxl; int n; int dfn[N],timestamp; void add_in(int x,int y,int z){ e[++idx]=y; ne[idx]=h[x]; w[idx]=z; h[x]=idx; } void dfs(int u,int fa){ //树的直径 dfn[u]=++timestamp; //记录一下访问了该节点 int v; f[u]=0; for(int i=h[u];i;i=ne[i]){ v=e[i]; if(v==fa) continue; dfs(v,u); mxl=max(mxl,f[u]+f[v]+w[i]); f[u]=max(f[u],f[v]+w[i]); } } int main(){ cin>>n; for(int i=1;i<=n;i++){ cin>>col[i]; } int x,y; for(int i=1;i<n;i++){ cin>>x>>y; if(col[x]==col[y]) continue; //两点颜色相同则不用建边 add_in(x,y,1); add_in(y,x,1); } int res=0; for(int i=1;i<=n;i++){ if(!dfn[i]) //该节点未被访问过 dfs(i,0); } cout<<mxl+1<<endl; //因为树的直径计算的是经过边的条数,因此需+1 return 0; }
Information
- ID
- 147
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By